If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+48x=0
a = 5; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·5·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*5}=\frac{-96}{10} =-9+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*5}=\frac{0}{10} =0 $
| 2z+9•75-7z=-5.15 | | -5(r+2)=-64 | | 15p-(5(p-1)-9=0 | | X+3=-3x+3 | | 96x5=270 | | 13x+1=7x+49 | | -4–1.3x+12x=10.7x–4 | | 40=-1/3(9x-30)+2 | | y^2=144/36 | | 10x-8=9x+18 | | 7b+10-3b=2(b-1) | | 2n+15+4n+33=180 | | 3/5(-3+3x)=72/5 | | -19x-17=-26 | | 4.9t^2-60t-200=0 | | 8x-5=2x-6 | | 2n+15+4n+33=90 | | 12y=78 | | 2/3(6j=9)=3j=7 | | 65=(3÷4)c-7 | | 4x+4=-4x+8 | | 1/10y+6=-13 | | 6x-8=4x+7 | | 13+l=34 | | 9x+5−8x+14=20 | | 7+√3s-8=2 | | 1/10y-6=-13 | | 6x+12=3x+16 | | 5x-3-2x=x+7+6x | | (2/3)+x=(4/3) | | n/605n/12=1/6 | | 2/3+x=(4/3) |